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0.4^3-5x^2+3x+7=0
We add all the numbers together, and all the variables
-5x^2+3x+7.064=0
a = -5; b = 3; c = +7.064;
Δ = b2-4ac
Δ = 32-4·(-5)·7.064
Δ = 150.28
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(3)-\sqrt{150.28}}{2*-5}=\frac{-3-\sqrt{150.28}}{-10} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(3)+\sqrt{150.28}}{2*-5}=\frac{-3+\sqrt{150.28}}{-10} $
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